Watch exponential charging and discharging governed by the RC time constant
A capacitor stores charge on two parallel plates separated by a dielectric. Its capacitance C = ε₀A/d depends on plate area A and separation d. In an RC circuit, charging follows V(t) = V₀(1 − e^(−t/RC)) and discharging follows V(t) = V₀e^(−t/RC). The time constant τ = RC is the time to reach approximately 63% of the final voltage during charging, and the energy stored at full charge is U = ½CV².
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Sign in →A capacitor stores energy in the electric field between two parallel conducting plates separated by an insulating gap (vacuum or dielectric of permittivity κε₀). Capacitance C = κε₀A/d (κ = 1 for vacuum) relates plate geometry directly to charge-storage ability. Connect a capacitor and resistor in series with a battery and the charging voltage climbs as V_C(t) = V₀(1 − e^(−t/RC)) — an exponential approach, not a straight line. The time constant τ = RC sets the pace: after one τ the capacitor has reached ~63% of V₀; after five τ it is effectively full. Energy stored at full charge is U = ½CV². The simulation lets you sweep capacitance (μF), resistance (kΩ), and battery voltage, and you can alter plate geometry to watch how C = κε₀A/d shifts the curve in real time.
MisconceptionThe capacitor charges at a constant rate until it hits V₀, then stops — like filling a bucket from a steady tap.
CorrectCharging is exponential: the rate slows continuously because the growing V_C opposes the battery. V_C(t) = V₀(1 − e^(−t/RC)) approaches V₀ asymptotically and technically never reaches it exactly.
MisconceptionDoubling the resistance doubles the final charge on the capacitor.
CorrectThe final charge Q = CV₀ depends only on capacitance and voltage, not resistance. Resistance changes how fast the capacitor charges (via τ = RC), not how much charge it ultimately stores.
MisconceptionA fully charged capacitor in a DC circuit continues to draw current.
CorrectOnce V_C = V₀, the voltage across R is zero and current is zero. The capacitor blocks steady DC — that is its defining steady-state behavior.
MisconceptionEnergy stored in a capacitor equals QV, not ½CV².
CorrectQV would be the energy if the full voltage V were present during the entire charging process. Because voltage builds from 0 to V₀, the actual work done is the integral ∫₀^Q V dq = Q²/(2C) = ½CV².
MisconceptionIncreasing plate separation increases capacitance because the plates are farther apart and can hold more charge.
CorrectCapacitance C = ε₀A/d decreases as d increases. For a given charge per unit area, the electric field E is unchanged, but the voltage V = Ed grows with d, so C = Q/V decreases.
τ = RC is the time for the charging voltage to reach (1 − 1/e) ≈ 63.2% of V₀, or for the discharging voltage to fall to 1/e ≈ 36.8% of its starting value. Physically it balances how much charge the capacitor wants to hold (C) against how fast the circuit can deliver it (1/R). At t = 5τ the capacitor is within 0.7% of its final value — conventionally considered fully charged.
As V_C rises it opposes the battery more and more, so the driving voltage across R (= V₀ − V_C) shrinks continuously. Less voltage across R means less current, which means V_C grows more slowly. This self-limiting feedback is exactly what produces the exponential: dV_C/dt = (V₀ − V_C)/τ.
The simulation targets CHA-2.E (relating charge, voltage, and capacitance), CHA-2.F (parallel-plate geometry and C = κε₀A/d, with κ = 1 for the vacuum/air gap modeled here), and CHA-4.A (RC circuit transient analysis including the time-constant τ = RC and exponential charging/discharging). These codes are listed directly in the experiment's standards block.
The capacitor stores U = ½CV² = Q²/(2C). The battery delivers total energy QV₀ = CV₀², so exactly half — ½CV₀² — is dissipated in R as heat during charging, regardless of the value of R. This result surprises students because a larger R seems like it should waste less energy, but a larger R also means slower charging and longer time, and the two effects exactly cancel.
Yes. In parallel, C_total = C₁ + C₂, which increases τ = RC_total. In series, 1/C_total = 1/C₁ + 1/C₂, which decreases C_total and shortens τ. The same rules apply to the RC time constant: τ scales directly with whatever effective capacitance the resistor sees.
Mathematically no — I(t) = (V₀/R)e^(−t/τ) decays to zero only as t → ∞. Practically, after 5τ the current is less than 0.7% of its initial value and is treated as zero. In the simulation you can observe the current trace flatten and become indistinguishable from the axis well before the time axis ends.