Map equipotential surfaces and understand work done by electric fields
Electric potential V at a point is the work done per unit positive charge to bring a test charge from infinity to that point. For a point charge, V = kq/r, and the field points in the direction of decreasing potential: E = −ΔV/Δx. Equipotential lines connect points of equal potential; they are always perpendicular to electric field lines. No work is done moving a charge along an equipotential surface.
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Sign in →Electric potential V at a point in space is the work per unit positive charge required to bring a test charge quasi-statically from infinity to that point: V = kq/r for a single point charge (in joules per coulomb, or volts). Unlike the electric field — which is a vector quantity requiring geometric addition — potential is a scalar, so contributions from multiple charges sum algebraically: V_total = k∑(qᵢ/rᵢ). Equipotential lines connect points of equal V; they are always perpendicular to electric field lines because no work is done moving a charge along them. This simulation maps the full potential landscape as a color gradient, overlays equipotential contour lines, and lets you place one to three point charges to observe how their scalar fields superpose and how the resulting E field — obtained from E = −∇V — relates geometrically to the contours you see.
MisconceptionVoltage and electric field are the same thing — a high-voltage region has a strong electric field.
CorrectV (volts, J/C) is potential energy per unit charge at a point; E (N/C or V/m) is force per unit charge. The two are related by E = −dV/dr (or more generally E = −∇V). A region can have high potential but weak field — for example, inside a large hollow conductor (or a conducting sphere in electrostatic equilibrium) where V is large but E = 0.
MisconceptionEquipotential lines show where the electric field is strongest — they bunch together near high field.
CorrectClosely spaced equipotentials indicate a large potential gradient, which means a large field magnitude |E| = |dV/dr|. But the equipotential lines themselves are perpendicular to E, not parallel. The field points from high-V to low-V regions, crossing each contour at right angles.
MisconceptionMoving a charge along an equipotential line requires work because you are moving against the electric field.
CorrectBy definition, all points on an equipotential surface have the same V, so ΔV = 0. The electric field E is perpendicular to the equipotential by construction, so it exerts no tangential force on a charge moving along the surface. Therefore W = qΔV = 0: no work is done by the field (or against it) for any path that stays on a single equipotential.
MisconceptionElectric potential is always positive.
CorrectV = kq/r is negative for a negative source charge q, and can be negative at any point where the negative contributions outweigh positive ones. The simulation's color map uses cool colors for negative V and warm colors for positive V; the zero-potential equipotential is the transition between them and is visible as a distinct contour.
MisconceptionThe electric field points from low potential to high potential, toward positive charges.
CorrectThe field points from high potential to low potential: E = −∇V. Near a positive charge, V is highest close to the charge and decreases outward, so E points outward (away from the charge). Near a negative charge, V is most negative at the source, so E points inward toward the charge.
Electric potential V (volts = J/C) is a property of the field at a point in space, independent of any test charge. Electric potential energy U = qV is the energy stored when a charge q is placed at that point. Moving a +1 μC charge to a point where V = 100 V stores U = 10⁻⁴ J of energy; a −1 μC charge at the same point stores −10⁻⁴ J.
Standards CHA-2.C (electric potential from point charges, V = kq/r), CHA-2.D (potential energy ΔU = qΔV; work done by the field W_field = −qΔV; quasi-static external work W_ext = qΔV), and CHA-3.A (relationship between E and V, including equipotential lines perpendicular to field lines) are all directly exercised by this experiment's parameters and measurements.
The electric field is E = −∇V. The gradient of V points in the direction of maximum V increase — perpendicular to the surfaces of constant V (equipotentials). Since E is the negative gradient, it points perpendicular to equipotentials in the direction of decreasing V. A tangential component of E along an equipotential would imply ΔV ≠ 0 along that surface, which contradicts the definition.
Click two points on the canvas to read V_i and V_f. Use the convention: ΔU = q(V_f − V_i); work done by the field W_field = −ΔU = q(V_i − V_f); work done by an external agent quasi-statically W_ext = +ΔU = q(V_f − V_i). Moving a positive charge from low-V to high-V means V_f > V_i, so ΔU > 0: the field does negative work and the external agent does positive work. Set test_charge_sign to match the sign of q.
Set charge_count = 2 and charge2_x near 0. The equipotential lines cluster tightly between the charges (strong field, steep V gradient) and bulge outward near each charge. Far from the pair, the pattern approaches that of a dipole — equipotentials elongated perpendicular to the charge axis. The zero-volt equipotential forms a plane midway between equal and opposite charges.
Electric potential is a scalar — it has magnitude and sign but no direction. This means V_total = k∑(qᵢ/rᵢ) involves only algebraic addition, with no need to resolve vector components. By contrast, calculating the total electric field requires adding vectors, which is more involved. Superposition of potentials is almost always simpler than superposition of fields, and this simulation makes both visible for comparison.